0.1 Homothety
Theorem 0.1.1: Monge’s Theorem
The pairwise external similitude centers of three distinct circles are collinear.
Proof.
First, consider the following diagram.
From the diagram above, it is evident that \(X,Y,Z\) are collinear if and only if Menelaus’ Theorem holds for \(\triangle {O_1O_2O_3}\). In other words, it suffices to show that the following equation holds. \[ \frac {O_2 X}{O_1 X} \cdot \frac {O_3 Y}{O_2 Y} \cdot \frac {O_1 Z}{O_3 Z} = 1 \] Note that \(\frac {O_2 X}{O_1 X} = \frac {R_2}{R_1}\) by similar triangle. Similarly, \(\frac {O_3 Y}{O_2 Y} = \frac {R_3}{R_2}\) and \(\frac {O_1 Z}{O_3 Z} = \frac {R_1}{R_3}\). Because \(\frac {R_2}{R_1} \cdot \frac {R_3}{R_2} \cdot \frac {R_1}{R_3} = 1\), the theorem holds.